Scrigroup - Documente si articole

     

HomeDocumenteUploadResurseAlte limbi doc
ArhitecturaAutoCasa gradinaConstructiiInstalatiiPomiculturaSilvicultura


CALCULUL SCARA DIN BETON ARMAT MONOLIT

Constructii



+ Font mai mare | - Font mai mic



CALCULUL SCARA DIN BETON ARMAT MONOLIT

CALCULUL RAMPEI:

Evaluarea incarcarilor:

Incarcari permanente:



-greutate proprie placa rampa:

hrpl·γb.a·1.1=0.13·2500·1.1=357.5

-greutate proprie trepte:

htrech·γb.s·1.1=0.0734·2400·1.1=193.776 daN/m

Atriunghi=Adreptunghi

-greutate finisaj trepte:

hechfinisaj.· γmozaic ·1.3=0.138.·2350·1.3=421

2 Apatrat= Adreptunghi

btr    ·4 cm+htr·2 cm=hechfinisaj·

= hechfinisaj=0.138 m.

-tencuiala rampa:

0.015· γmortar·1.3=0.015·1900·1.3=37.05

=1009.32 daN/m2

Incarcarea temporare:

Incarcarea utila:

=300·1.4=420 daN/m2

lr'==2.60

=0.648

=32.94

cos=0.83

g=g'·lt·cos=1009.32·0.83·0.9=837.73 daN/m2

p=p'·lt·cos2=420 0.83)2·0.9=289.33 daN/m2

M===952 daN/m

z=0.9·h0

h0=13-=11.1 cm

Aa===3.17 cm2 =>510 cm/m

Calculul podestului de nivel curent:

A .Evaluarea incarcarilor:

  • Incarcarii permanente:

-greutate proprie placa de podest:

hpodestplaca··1.1=0.15·2500·1.1= daN/m2

-greutate mozaic turnat:

0.05·2300·1.3=149.5 daN/m2

-tencuiala:

0.015·1900·1.3= daN/m2

daN/m2

Incarcari temporare:

-utila:

300·1.4= daN/m2

daN/m2

q=g+p=599+420= daN/m2

P=q·lx·ly=1019·0.7·2.1= daN/m2

lx =70 cm

ly =2.10m

mxr=12.62

mxm=23.68

mym=27.94

Mxr==118.69

AaxrA = =0.356

Mxm==63.25

AaxmA = =0.189

Mym==53.61

AaymA = =0.160

Cazul B:

Incarcarea din reactiunea rampei pe 1m liniar de latura libera rezulta:

qc=g'·lt·lr/2+(p'·lt)·lr/2=1009.32·1.00·2.60/2+420·1.00·2.16/2=

=1312.1+453.60=1765.7 daN/m2

S=qc·lx=1765.7·2.10=3707.9 daN

0.34

mxr=6.38

mxm=1.38

mym=5.4

Mxr==581.1 daN/m

AaxrB=1.74 cm2

Mxm==304.42 daN/m

AaxmB=0.91 cm2

Mym==38.46 daN/m

AaymB=0.115 cm2

Aaxrtotal= AaxrA+ AaxrB=0.356+1.74=2.09 cm2 =>5

Aaxmtotal= AaxmA+AaxmB=0.91+0.189=1.09 cm2 =>5

Aaymtotal= AaymA+ AaymB=0.115+0.160=0.275 cm2    =>5

Calculul podestului intermediar:

Cazul de incarcare A:

q=g+p=1019 daN/m2

P=q·lx·ly=1019·0.7·2.1= daN/m2

lx =70 cm

ly =2.10m

mxr=12.62

mxm=23.68

mym=27.94

Mxr==118.69

AaxrA = =0.356

Mxm==63.25

AaxmA = =0.189

Mym==53.61

AaymA = =0.160

Cazul B:

Incarcarea din reactiunea rampei pe 1m liniar de latura libera rezulta:

qc=g'·lt·lr/2+(p'·lt)·lr/2=1009.32·1.00·2.60/2+420·1.00·2.16/2=

=1312.1+453.60=1765.7 daN/m2

S=qc·lx=1765.7·2.10=3707.9 daN

0.34

mxr=6.38

mxm=1.38

mym=5.4

Mxr==581.1 daN/m

AaxrB=1.74 cm2

Mxm==304.42 daN/m

AaxmB=0.91 cm2

Mym==38.46 daN/m

AaymB=0.115 cm2

Aaxrtotal= AaxrA+ AaxrB=0.356+1.74=2.09 cm2 =>5

Aaxmtotal= AaxmA+AaxmB=0.91+0.189=1.09 cm2 =>5

Aaymtotal= AaymA+ AaymB=0.115+0.160=0.275 cm2    =>5



Politica de confidentialitate | Termeni si conditii de utilizare



DISTRIBUIE DOCUMENTUL

Comentarii


Vizualizari: 3780
Importanta: rank

Comenteaza documentul:

Te rugam sa te autentifici sau sa iti faci cont pentru a putea comenta

Creaza cont nou

Termeni si conditii de utilizare | Contact
© SCRIGROUP 2024 . All rights reserved