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Inverter circuit - 800mA of 12V power

electronics



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This inverter circuit can provide up to 800mA of 12V power from a 6V supply. For example, you could run 12V car accessories in a 6V (British?) car. The circuit is simple, about 75% efficient and quite useful. By changing just a few components, you can also modify it for different voltages.

Schematic



Parts

Part

Total Qty.

Description

Substitutions

R1, R4

2.2K 1/4W Resistor

R2, R3

4.7K 1/4W Resistor

R5

1K 1/4W Resistor

R6

1.5K 1/4W Resistor

R7

33K 1/4W Resistor

R8

10K 1/4W Resistor

C1,C2

0.1uF Ceramic Disc Capacitor

C3

470uF 25V Electrolytic Capcitor

D1

1N914 Diode

D2

1N4004 Diode

D3

12V 400mW Zener Diode

Q1, Q2, Q4

BC547 NPN Transistor

Q3

BD679 NPN Transistor

L1

See Notes

MISC

Heatsink For Q3, Binding Posts (For Input/Output), Wire, Board

Notes

1. L1 is a custom inductor wound with about 80 turns of 0.5mm magnet wire around a toroidal core with a 40mm outside diameter.

2. Different values of D3 can be used to get different output voltages from about 0.6V to around 30V. Note that at higher voltages the circuit might not perform as well and may not produce as much current. You may also need to use a larger C3 for higher voltages and/or higher currents.

3. You can use a larger value for C3 to provide better filtering.

4. The circuit will require about 2A from the 6V supply to provide the full 800mA at 12V.



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